Electromagnetic Induction and Alternating Currents

The rms value of the domestic AC supply in India is 220 V. Its peak value is about:

The time period of a 50 Hz alternating voltage is:

The average value of a sinusoidal alternating current over one complete cycle is:

An alternating voltage is given by v = 200 sin(314t) volt. Its rms value and frequency are about:

A current i = (3 + 4 sin ωt) A, a steady current plus a sinusoidal current, flows through a resistor. The rms value of this current is about:

For a 50 Hz alternating current, the time taken by the current to rise from zero to its peak value is:

An AC ammeter connected in a circuit reads the:

An alternating current of peak value 2√2 A flows through a 10 Ω resistor. The average power dissipated is:

An alternating voltage is v = 100 sin(100πt + π/6) volt. Its value at t = 0 is:

For a 50 Hz sinusoidal voltage starting from zero, the time after which its instantaneous value first equals its rms value is:

The peak-to-peak value of a sinusoidal voltage of rms value 220 V is about:

In phasor representation, a sinusoidal alternating voltage is represented by:

An alternating voltage has a peak value of 100√2 V. Find its rms value in volt.

An alternating voltage is v = 311 sin(100πt) volt. Find its frequency in hertz.

A sinusoidal current has a peak value of 11 A. Find its average value over a positive half-cycle in ampere, to the nearest integer.

A current i = (3 + 4√2 sin ωt) A, a steady current plus a sinusoidal current, flows through a resistor. Find its rms value in ampere.