Kirchhoff's junction rule (first law) is a consequence of the conservation of:
Kirchhoff's junction rule (first law) is a consequence of the conservation of:
Kirchhoff's loop rule (second law) is a consequence of the conservation of:
At a junction, currents of 3 A and 5 A flow in, and a current of 2 A flows out along one wire. The current in the remaining wire at the junction is:
Two batteries, of emf 6 V and 4 V, each with internal resistance 1 Ω, are connected in parallel with like terminals together, and a 2 Ω resistor is connected across them. The current through the 2 Ω resistor is:
Two batteries, of emf 6 V and 4 V, each with internal resistance 1 Ω, are connected in parallel with like terminals together, and a 2 Ω resistor is connected across them. The current through the 4 V battery is:
Three branches are connected in parallel between points A and B. Branch 1: a 12 V battery in series with a 2 Ω resistor. Branch 2: a 2 Ω resistor alone. Branch 3: a 3 V battery in series with a 2 Ω resistor. Both batteries have negligible internal resistance and their positive terminals face A. The current through the branch-2 resistor is:
Three branches are connected in parallel between points A and B. Branch 1: a 12 V battery in series with a 2 Ω resistor. Branch 2: a 2 Ω resistor alone. Branch 3: a 3 V battery in series with a 2 Ω resistor. Both batteries have negligible internal resistance and their positive terminals face A. The current in the 3 V battery is:
While applying the loop rule, a resistor R carrying current I is traversed in the same direction as the current. The change in potential to be written is:
The algebraic sum of the potential differences around any closed loop of a circuit is:
An ideal 12 V battery is connected across a 2 Ω and a 4 Ω resistor in series. A 5 μF capacitor is connected directly across the 4 Ω resistor. In the steady state, the charge on the capacitor is:
A single loop contains a 10 V cell and a 4 V cell connected so that their emfs oppose each other, each having internal resistance 0.5 Ω, together with an external resistor of 2 Ω. The current in the loop is:
A single loop contains a 10 V cell and a 4 V cell connected so that their emfs oppose each other, each having internal resistance 0.5 Ω, together with an external resistor of 2 Ω. The terminal potential difference across the 4 V cell is:
Three resistors of 2 Ω, 2 Ω and 1 Ω meet at a common point O. Their other ends are held at potentials of 10 V, 4 V and 1 V respectively. The potential of point O is:
At a junction, currents of 4 A and 6 A flow in. One wire carries 3 A out of the junction. Find the current (in ampere) leaving through the only other wire.
A battery of emf 9 V and internal resistance 1 Ω is connected to a 2 Ω and a 6 Ω resistor in series. Find the potential difference (in volt) across the 6 Ω resistor.
An ideal 10 V battery is connected across a 3 Ω and a 2 Ω resistor in series. A 4 μF capacitor is connected across the 3 Ω resistor. Find the steady-state charge on the capacitor in microcoulomb.