A current of 2 A flows through a 10 Ω resistor. The power dissipated in it is:
A current of 2 A flows through a 10 Ω resistor. The power dissipated in it is:
A bulb is rated 100 W, 220 V. Its resistance when operating normally is:
A 100 W and a 60 W bulb, both rated for 220 V, are connected in series across a 220 V supply. Then:
One kilowatt hour (1 kWh) is equal to:
A 1000 W electric heater is used for 2 hours every day. The electrical energy it uses in 30 days is:
A bulb rated 100 W, 220 V is operated on a 110 V supply. Assuming its resistance does not change, the power it consumes is:
The heating coil of an electric heater is cut to half its length and connected to the same supply. The power of the heater:
Two identical heater coils connected in series across a supply boil a given quantity of water in time t. If they are connected in parallel across the same supply, the same water boils in:
A current of 2 A flows through a 5 Ω resistor for 1 minute. The heat produced is:
A fuse wire should have:
For resistors connected across a constant voltage, the power dissipated in a resistor is:
The current drawn by a 40 W, 220 V lamp when it works normally is about:
Two resistors connected in parallel across a supply dissipate powers in the ratio 2 : 1. If they are connected in series across the same supply, the ratio of the powers dissipated in them (same order) becomes:
A current of 3 A flows through a 4 Ω resistor. Find the power dissipated in watt.
A 1.5 kW heater runs for 4 hours. Find the energy consumed in kWh.
Find the resistance (in ohm) of the filament of a bulb rated 60 W, 120 V when it glows normally.
Three identical bulbs are connected as follows: two of them in parallel, and this pair in series with the third, across a supply. Assuming the resistances stay constant, find the ratio of the power in the third (series) bulb to the power in either of the parallel bulbs.