A cell of emf 2 V and internal resistance 0.5 Ω is connected across an external resistance of 3.5 Ω. The current drawn is:
A cell of emf 2 V and internal resistance 0.5 Ω is connected across an external resistance of 3.5 Ω. The current drawn is:
A cell of emf 2 V and internal resistance 0.5 Ω is connected across an external resistance of 3.5 Ω. The terminal potential difference of the cell is:
A cell has emf 1.5 V and internal resistance 0.3 Ω. The current when its terminals are short-circuited by a thick wire of negligible resistance is:
A 12 V battery of internal resistance 0.5 Ω is being charged by a current of 2 A. The potential difference across its terminals during charging is:
n identical cells, each of emf E and internal resistance r, are connected in series across an external resistance R. The current is:
m identical cells, each of emf E and internal resistance r, are connected in parallel (like terminals together) across an external resistance R. The current through R is:
The terminal voltage of a cell is 2.2 V on open circuit and falls to 1.8 V when a 5 Ω resistor is connected across it. The internal resistance of the cell is about:
A cell of emf 6 V and internal resistance 2 Ω is connected to a variable external resistor. The maximum power that can be delivered to the external resistor is:
The emf of a cell is equal to:
A cell of emf 2 V (internal resistance 1 Ω) and a cell of emf 1.5 V (internal resistance 0.5 Ω) are connected in series with their positive terminals joined together (opposing), and this combination is connected across a 1 Ω resistor. The current is:
Two cells of emfs 2 V and 1 V, each with internal resistance 1 Ω, are connected in parallel with like terminals together. The emf and internal resistance of the equivalent single cell are:
For a cell, the graph of terminal voltage V (y-axis) against the current I drawn (x-axis) is a straight line. Its intercept on the V-axis and its slope are respectively:
A cell of internal resistance 0.25 Ω delivers a current of 2 A. The 'lost voltage' inside the cell is:
A cell of emf E and internal resistance r is connected to an external resistance R = 3r. The terminal voltage of the cell is:
A cell of emf 6 V and internal resistance 1 Ω is connected across a 2 Ω resistor. Find the current in ampere.
A battery of emf 12 V and internal resistance 0.4 Ω supplies a current of 2.5 A. Find its terminal voltage in volt.
Four cells, each of emf 1.5 V and internal resistance 0.5 Ω, are connected in series across a 4 Ω resistor. Find the terminal voltage (in volt) of the battery.
A cell drives a current of 2 A through a 1 Ω resistor and a current of 1 A through a 2.5 Ω resistor. Find the emf of the cell in volt.