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Magnetic Effects of Current and Magnetism
JEE Physics · 160 questions. Try each one, then check the answer and solution.
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Q1.AI-generated practiceSingle-correct MCQEasy
A proton moves with a speed of 2 × 106 m/s perpendicular to a uniform magnetic field of 0.5 T. The magnitude of the force on it is (e = 1.6 × 10-19 C):
Q2.AI-generated practiceSingle-correct MCQEasy
The work done by a uniform magnetic field on a charged particle moving through it is:
Q3.AI-generated practiceSingle-correct MCQMedium
An electron moving at 1 × 106 m/s enters a uniform magnetic field of 1 × 10-3 T perpendicular to its velocity. The radius of its circular path is about (me = 9.1 × 10-31 kg, e = 1.6 × 10-19 C):
Q4.AI-generated practiceSingle-correct MCQMedium
A charged particle moves in a circle in a uniform magnetic field. If its speed is doubled, its time period of revolution:
Q5.AI-generated practiceSingle-correct MCQMedium
A charged particle enters a uniform magnetic field with its velocity making an angle of 30° with the field. Its path in the field is:
Q6.AI-generated practiceSingle-correct MCQHard
A proton moving at 4 × 105 m/s enters a uniform magnetic field of 0.1 T with its velocity at 60° to the field. The pitch of its helical path is about (mp = 1.67 × 10-27 kg, e = 1.6 × 10-19 C):
Q7.AI-generated practiceSingle-correct MCQMedium
In a region with crossed electric and magnetic fields, E = 3 × 104 V/m and B = 0.2 T, mutually perpendicular. Charged particles pass through undeflected (moving perpendicular to both fields) if their speed is:
Q8.AI-generated practiceSingle-correct MCQMedium
A proton and an α-particle have the same kinetic energy and move perpendicular to the same uniform magnetic field. The ratio of their radii rp : rα is (mα = 4mp, qα = 2e):
Q9.AI-generated practiceSingle-correct MCQHard
An electron and a proton move with the same speed perpendicular to the same uniform magnetic field. The ratio of the radius of the proton's path to that of the electron's path is:
Q10.AI-generated practiceSingle-correct MCQEasy
A positively charged particle moves along the +x axis in a uniform magnetic field directed along +y. The magnetic force on it is directed along:
Q11.AI-generated practiceSingle-correct MCQMedium
An electron moves along the +x axis in a uniform magnetic field directed along +z. The magnetic force on the electron is directed along:
Q12.AI-generated practiceSingle-correct MCQHard
A particle of mass m and charge q, initially at rest, is accelerated through a potential difference V and then enters a uniform magnetic field B perpendicular to its velocity. The radius of its circular path is:
Q13.AI-generated practiceSingle-correct MCQMedium
The frequency of revolution of a proton moving in a uniform magnetic field of 1 T is about (mp = 1.67 × 10-27 kg, e = 1.6 × 10-19 C):
Q14.AI-generated practiceSingle-correct MCQHard
A charged particle is released from rest in a region where a uniform electric field and a uniform magnetic field are parallel to each other. The particle moves:
Q15.AI-generated practiceNumerical valueEasy
A charge of 2 μC moves with a speed of 5 × 103 m/s perpendicular to a uniform magnetic field of 0.4 T. If the force on it is x × 10-3 N, find x.
Q16.AI-generated practiceNumerical valueMedium
A particle of mass 2 × 10-26 kg and charge 1 × 10-18 C moves with speed 2 × 105 m/s perpendicular to a uniform magnetic field of 0.1 T. Find the radius of its path in cm.
Q17.AI-generated practiceNumerical valueMedium
In a velocity selector, the electric field is 6 × 103 V/m and the magnetic field is 0.03 T, perpendicular to each other. If the speed of the undeflected particles is x × 105 m/s, find x.
Q18.AI-generated practiceNumerical valueHard
A proton enters a region of uniform magnetic field of width 5 cm, moving perpendicular both to the field and to the boundary of the region. Inside the field the radius of its circular path would be 10 cm. Find the angle (in degrees) through which the proton is deviated when it leaves the field region.
Q19.AI-generated practiceAssertion–ReasonMedium
Assertion (A): The kinetic energy of a charged particle moving in a uniform magnetic field remains constant. Reason (R): The magnitude of the magnetic force on a moving charge is proportional to its charge.
Q20.AI-generated practiceAssertion–ReasonHard
Assertion (A): The time period of revolution of a charged particle in a uniform magnetic field is independent of its speed. Reason (R): The radius of the circular path of the particle does not depend on its speed.