The near point of a hypermetropic eye is 1 m. Assuming the normal near point is 25 cm, what type of lens is needed for correction, and roughly what power?

Using 1/v - 1/u = 1/f with u = -0.25 m (object at normal near point) and v = -1 m (image at the person's actual near point): 1/f = -1 - (-4) = 3, so f » +0.33 m, giving P = +3 D; a convex lens is required.